Fixes #19599
5.5 KiB
% The Guide to Rust Strings
Strings are an important concept to master in any programming language. If you come from a managed language background, you may be surprised at the complexity of string handling in a systems programming language. Efficient access and allocation of memory for a dynamically sized structure involves a lot of details. Luckily, Rust has lots of tools to help us here.
A string is a sequence of unicode scalar values encoded as a stream of UTF-8 bytes. All strings are guaranteed to be validly-encoded UTF-8 sequences. Additionally, strings are not null-terminated and can contain null bytes.
Rust has two main types of strings: &str
and String
.
&str
The first kind is a &str
. This is pronounced a 'string slice'.
String literals are of the type &str
:
let string = "Hello there.";
Like any Rust type, string slices have an associated lifetime. A string literal
is a &'static str
. A string slice can be written without an explicit
lifetime in many cases, such as in function arguments. In these cases the
lifetime will be inferred:
fn takes_slice(slice: &str) {
println!("Got: {}", slice);
}
Like vector slices, string slices are simply a pointer plus a length. This
means that they're a 'view' into an already-allocated string, such as a
&'static str
or a String
.
String
A String
is a heap-allocated string. This string is growable, and is also
guaranteed to be UTF-8.
let mut s = "Hello".to_string();
println!("{}", s);
s.push_str(", world.");
println!("{}", s);
You can coerce a String
into a &str
with the as_slice()
method:
fn takes_slice(slice: &str) {
println!("Got: {}", slice);
}
fn main() {
let s = "Hello".to_string();
takes_slice(s.as_slice());
}
You can also get a &str
from a stack-allocated array of bytes:
use std::str;
let x: &[u8] = &[b'a', b'b'];
let stack_str: &str = str::from_utf8(x).unwrap();
Best Practices
String
vs. &str
In general, you should prefer String
when you need ownership, and &str
when
you just need to borrow a string. This is very similar to using Vec<T>
vs. &[T]
,
and T
vs &T
in general.
This means starting off with this:
fn foo(s: &str) {
and only moving to this:
fn foo(s: String) {
If you have good reason. It's not polite to hold on to ownership you don't need, and it can make your lifetimes more complex.
Generic functions
To write a function that's generic over types of strings, use &str
.
fn some_string_length(x: &str) -> uint {
x.len()
}
fn main() {
let s = "Hello, world";
println!("{}", some_string_length(s));
let s = "Hello, world".to_string();
println!("{}", some_string_length(s.as_slice()));
}
Both of these lines will print 12
.
Comparisons
To compare a String to a constant string, prefer as_slice()
...
fn compare(x: String) {
if x.as_slice() == "Hello" {
println!("yes");
}
}
... over to_string()
:
fn compare(x: String) {
if x == "Hello".to_string() {
println!("yes");
}
}
Converting a String
to a &str
is cheap, but converting the &str
to a
String
involves an allocation.
Indexing strings
You may be tempted to try to access a certain character of a String
, like
this:
let s = "hello".to_string();
println!("{}", s[0]);
This does not compile. This is on purpose. In the world of UTF-8, direct indexing is basically never what you want to do. The reason is that each character can be a variable number of bytes. This means that you have to iterate through the characters anyway, which is an O(n) operation.
There's 3 basic levels of unicode (and its encodings):
- code units, the underlying data type used to store everything
- code points/unicode scalar values (char)
- graphemes (visible characters)
Rust provides iterators for each of these situations:
.bytes()
will iterate over the underlying bytes.chars()
will iterate over the code points.graphemes()
will iterate over each grapheme
Usually, the graphemes()
method on &str
is what you want:
let s = "u͔n͈̰̎i̙̮͚̦c͚̉o̼̩̰͗d͔̆̓ͥé";
for l in s.graphemes(true) {
println!("{}", l);
}
This prints:
u͔
n͈̰̎
i̙̮͚̦
c͚̉
o̼̩̰͗
d͔̆̓ͥ
é
Note that l
has the type &str
here, since a single grapheme can consist of
multiple codepoints, so a char
wouldn't be appropriate.
This will print out each visible character in turn, as you'd expect: first "u͔", then
"n͈̰̎", etc. If you wanted each individual codepoint of each grapheme, you can use .chars()
:
let s = "u͔n͈̰̎i̙̮͚̦c͚̉o̼̩̰͗d͔̆̓ͥé";
for l in s.chars() {
println!("{}", l);
}
This prints:
u
͔
n
̎
͈
̰
i
̙
̮
͚
̦
c
̉
͚
o
͗
̼
̩
̰
d
̆
̓
ͥ
͔
e
́
You can see how some of them are combining characters, and therefore the output looks a bit odd.
If you want the individual byte representation of each codepoint, you can use
.bytes()
:
let s = "u͔n͈̰̎i̙̮͚̦c͚̉o̼̩̰͗d͔̆̓ͥé";
for l in s.bytes() {
println!("{}", l);
}
This will print:
117
205
148
110
204
142
205
136
204
176
105
204
153
204
174
205
154
204
166
99
204
137
205
154
111
205
151
204
188
204
169
204
176
100
204
134
205
131
205
165
205
148
101
204
129
Many more bytes than graphemes!