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std: Swap the argument order of list::foldl to match vec::foldl

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This commit is contained in:
Brian Anderson 2012-03-15 14:15:49 -07:00
parent 5e8004d493
commit 7e0fa3f852
1 changed files with 4 additions and 4 deletions
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8
src/libstd/list.rs
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@ -27,7 +27,7 @@ accumulated result.
* z - The initial value
* f - The function to apply
"]
fn foldl<T: copy, U>(ls: list<U>, z: T, f: fn(T, U) -> T) -> T {
fn foldl<T: copy, U>(z: T, ls: list<U>, f: fn(T, U) -> T) -> T {
let mut accum: T = z;
iter(ls) {|elt| accum = f(accum, elt);}
accum
@ -180,8 +180,8 @@ mod tests {
fn add(&&a: uint, &&b: int) -> uint { ret a + (b as uint); }
let l = from_vec([0, 1, 2, 3, 4]);
let empty = list::nil::<int>;
assert (list::foldl(l, 0u, add) == 10u);
assert (list::foldl(empty, 0u, add) == 0u);
assert (list::foldl(0u, l, add) == 10u);
assert (list::foldl(0u, empty, add) == 0u);
}
#[test]
@ -190,7 +190,7 @@ mod tests {
a - b
}
let l = from_vec([1, 2, 3, 4]);
assert (list::foldl(l, 0, sub) == -10);
assert (list::foldl(0, l, sub) == -10);
}
#[test]